Stat 1040
Chapter 14 Solutions
-
- (1/6)*(1/6) = 1/36.
- 6/36 = 1/6. (Use the chart of possible rolls.)
-
Option (i) is better, because if the first card isn't a queen, you still
have a shot at it on the second card.
-
"If you want to find the chance that at least one of the two events will
happen, check to see if they are mutually exclusive. If so, you can add the
chances."
"If you want to find the chance that both will happen, check to see if
they are independent. If so, you can multiply the chances."
- 1 - (3/5)^4 = (about) .87.
-
1. You can't avoid drawing a two
-
List out the possible draws in a chart like this:
| |
|
Box B |
| |
|
1 |
2 |
3 |
4 |
| |
1 |
11 |
12 |
13 |
14 |
| Box A |
2 |
21 |
22 |
23 |
24 |
| |
3 |
31 |
32 |
33 |
34 |
- 3/12.
- 3/12.
- 6/12.
-
Option (ii) is better, giving you 3 chances in 6 to win (each time). Option (i)
only gives you 2 chances in 6 to win (each time).
- (13/52)*(12/51)*(11/50) = (about) .01.
- (39/52)*(38/51)*(37/50) = (about) .41.
- 1 - (13/52)*(12/51)*(11/50) = .99. (This is the opposite of (a).)