Stat 1040
Chapter 16 Solutions
- Option (iii) is the best because the chance error is not likely
to be exactly zero, but it is likely to be small compared to the number of
draws.
- Both are wrong. Luck and the law of averages are irrelevant
because each spin is independent of those that go before. The chances stay
the same.
- 60 rolls. To win, you need a large percentage error, and that
is more likely in 60 rolls.
- 600 rolls - now you want a small percentage error.
- 600 rolls again - you want a small percentage error.
- 60 rolls because to get exactly the expected value means
getting exactly zero chance error, and that is more likely with
fewer rolls.
- Possibility (i) is more likely because you want the
percentage error to be at least 66 2/3% - 50% = 16 2/3%. The percentage
error is more likely to be at least 16 2/3% in the short run.
- The score is like the sum of 25 draws from a box with one
ticket marked "4" and 4 tickets marked "-1".
- The net gain is like the sum of 50 draws from a box with 4
tickets marked "$8" and 34 tickets marked "-$1".
- Option (ii) is the best. Say the percentage of reds in the
box is 60%. Then to win, we want the percentage error to be small, so that
the actual percentage will be greater than 50%. This is more likely
in the long run.
- 30/200 = 0.15.
- -20/200 = -0.1.
- average = sum/200.
- They are the same because 5/200 = .025.